# Line slope calculator 9x+7y=79

**Straight line given by points A[1; 10] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.2857x+11.2857

**Canonical form of the line equation:**9x+7y-79 = 0

**Parametric form of the line equation:**

x = 7t+1

y = -9t+10 ; t ∈ R

**Slope:**m = -1.2857

**Slope angle of line: φ =**-52°7'30″ = -0.9098 rad

**X intercept:**x

_{0}= 8.7778

**Y intercept:**y

_{0}= q = 11.2857

**Distance line from the origin:**d

_{0}= 6.9288

**The length of the segment AB: |AB| =**11.4018

**Vector: AB =**(7; -9)

**Normal vector: n =**(9; 7)

**Midpoint of the segment AB: M =**[4.5; 5.5]

**Perpendicular Bisector equation:**7x-9y+18 = 0

**Vector OA = (1; 10) ; |OA| = 10.0499**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 18**

**Angle ∠ AOB = 77°9'52″ = 1.3468 rad**