An elastic cord vibrates with a frequency of 2.7 Hz when a mass of 0.56 kg is hung from it. What will its frequency be if only 0.43 kg hangs from it?
f= 1/2PI sqrt (k/m)
figure k from the first data, then knowing k, figure the freq.
To find the frequency of the elastic cord when a different mass hangs from it, we can use the formula for the frequency of a vibrating string or cord:
f = (1/2π) * √(T/μ)
where:
f = frequency
T = tension in the cord
μ = mass per unit length of the cord
In this case, we can assume that the tension in the cord remains constant. Therefore, the only factor affecting the frequency is the mass per unit length of the cord.
Given that the frequency is 2.7 Hz when a mass of 0.56 kg hangs from it, we need to calculate the mass per unit length (μ) of the cord.
μ = mass / length
To proceed, we need to know the length of the cord. Without this information, we wouldn't be able to calculate the frequency for a different mass.