maths

if i have
k = 36.86 +/- 4.78
and
v = 113 +/- 9.92
both using 95% confidence limits and no true values of k or v given
am i right in saying that accuracy cannot be determined
and that v is a more precise measurement

my question was to comment on what can be said about
the precision
the accuracy
and which is measured more precisely

i know that the standard deviation and confidence limits are lower numerically for K
but proportionally as a percentage of the mean they are lower for V

i think this means that v is more accurate

i want to know if im correct in saying this

please can you just check this for me

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1. Yes, v is more accurate; it is the relative accuracy that is most important.

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posted by drwls

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