Use diagram to answer the following answer in 2 significant digits using scientific notation
if the rate of efficiency of the transfer of energy in this system were 15% between the first trophic level and the second trophic level the the amount of energy available to the second trophic level would be?
Diagram : a food chain diagram shows the following owls then mice with a number of 2,527kJ then grasshoppers with a number of 17,380kJ then grains, grasses, weeds with a number of 120,500 kJ from top down
First, we need to calculate the amount of energy transferred from one trophic level to the next.
Energy available to mice = 2,527 kJ
Energy available to grasshoppers = 17,380 kJ
Efficiency of energy transfer = 15% = 0.15
Energy transferred from mice to grasshoppers = 2,527 kJ * 0.15 = 379.05 kJ
Energy available to grasshoppers after transfer = 17,380 kJ + 379.05 kJ = 17,759.05 kJ
Now, we need to find the efficiency of the transfer of energy from grasshoppers to the next trophic level (grains, grasses, weeds).
Energy available to grains, grasses, weeds = 120,500 kJ
Efficiency of energy transfer = 15% = 0.15
Energy transferred from grasshoppers to grains, grasses, weeds = 17,759.05 kJ * 0.15 = 2,663.8575 kJ
Energy available to grains, grasses, weeds after transfer = 120,500 kJ + 2,663.8575 kJ = 123,163.8575 kJ
Therefore, the amount of energy available to the second trophic level (grains, grasses, weeds) is approximately 1.23 x 10^5 kJ.