Lebron's average bowling score for the season is 180 with a standard deviation of 28 use technology to determine which of the following represents the probability the LeBron records a score higher than 200
To find the probability that LeBron records a score higher than 200, we need to calculate the z-score first.
The z-score formula is:
z = (X - μ) / σ
Where:
X = 200 (score we want to find the probability for)
μ = 180 (average score)
σ = 28 (standard deviation)
Calculating the z-score:
z = (200 - 180) / 28
z = 20 / 28
z = 0.71429
Next, we need to find the probability corresponding to this z-score using a standard normal distribution table or a calculator.
Using a calculator or software, the probability that LeBron records a score higher than 200 is approximately 0.2407 or 24.07%.