How do you find the H-Shift.
My problem is y=5 sin(3x-pi/2).

  1. 👍
  2. 👎
  3. 👁
  1. Do you mean horizontal shift?

    Look at this:

    (3x-PI/2)= 3(x-PI/6)

    see the PI/6 term?

    1. 👍
    2. 👎
  2. Do you mean where does the function cross the x axis first after x = 0?
    If so it is when
    3x-pi/2 = 0
    x = pi/6

    1. 👍
    2. 👎
  3. yes I meant horizontal shift. so PI/6 is the answer?

    1. 👍
    2. 👎
  4. Jennifer, graph it starting at x = 0 and go to x = pi/3
    see where it crosses the axis

    1. 👍
    2. 👎
  5. then what's the ending point?

    1. 👍
    2. 👎
  6. It is a sine function. It goes on and on forever. The shift is just how much it is offset from the origin by being sin(3x-pi/2) instead of being sin(3x)

    1. 👍
    2. 👎
  7. never mind. I get it.

    1. 👍
    2. 👎
  8. atta go :)

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. Pre-Calc/Trig...

    Help me please. Which of the following accurately depicts the transformation of y=x^2 to the function shown below? y=5(x-2)^2+1 A. Shift 5 units right, stretch vertically by a factor of 2, then shift up 1 unit. B. Shift up 1 unit,

  2. calculus

    Find the points on the curve y= (cos x)/(2 + sin x) at which the tangent is horizontal. I am not sure, but would I find the derivative first: y'= [(2 + sin x)(-sin x) - (cos x)(cos x)]/(2 + sin x)^2 But then I don't know what to

  3. Math - Linear Approximation

    a) Find a linear approximation of y=sinx at x=pi/6 b) use part (a) to approximate sin(61pi/360) and sin(59pi/360) I just really have no idea how to approach this problem. I know the formula is y=f(a)+f'(a)(x-a). Does that mean it

  4. inverse

    If f(x)=cosx + 3 how do I find f inverse(1)? Thanks y = cos(x) + 3 the inverse of this is x = cos(y) + 3 solve for y and you have your inverse The cos function only has a range of [-1,1], so the range of f(x) is [2,4]. this means

  1. calculus

    Find complete length of curve r=a sin^3(theta/3). I have gone thus- (theta written as t) r^2= a^2 sin^6 t/3 and (dr/dt)^2=a^2 sin^4(t/3)cos^2(t/3) s=Int Sqrt[a^2 sin^6 t/3+a^2 sin^4(t/3)cos^2(t/3)]dt =a Int

  2. Calculus AP

    Evaluate the integral interval from [0 to pi] t sin(3t)dt Use integration by parts u=t and dv=sin(3t)dt. then du=dt and v=-cos(3t)/3 here is my problem but Im having problem to solve with pi. ∫t sin(3t)dt = -tcos(3t)/3 -

  3. trig

    The expression 4 sin x cos x is equivalent to which of the following? (Note: sin (x+y) = sin x cos y + cos x sin y) F. 2 sin 2x G. 2 cos 2x H. 2 sin 4x J. 8 sin 2x K. 8 cos 2x Can someone please explain how to do this problem to

  4. Calculus 12th grade (double check my work please)

    1.)Find dy/dx when y= Ln (sinh 2x) my answer >> 2coth 2x. 2.)Find dy/dx when sinh 3y=cos 2x A.-2 sin 2x B.-2 sin 2x / sinh 3y C.-2/3tan (2x/3y) D.-2sin2x / 3 cosh 3yz...>> my answer. 2).Find the derivative of y=cos(x^2) with

  1. Precalculus

    sin^2(2x)=2sinxcosx. Find all solutions to each equation in the interval [0, 2pi) So I started off changing 2sinxcosx = sin(2x), and my equation ended as sin^2(2x) = sin(2x). I subtracted sin(2x) by both sides and factored out

  2. statitstics

    A warehouse employs 22 workers on first shift and 14 workers on second shift. Eight workers are chosen at random to be interviewed about the work environment. Find the Probability of choosing: A. All first-shift workers B. All

  3. Trig

    If angle A is 45 degrees and angle B is 60 degrees. Find sin(A)cos(B), find cos(A)sin(B), find sin(A)sin(B), and find cos(A)cos(B) The choises for the first are: A. 1/2[sin(105)+sin(345)] B. 1/2[sin(105)-sin(345)] C.

  4. math

    I'm trying to find the convolution f*g where f(t)=g(t)=sin(t). I set up the integral and proceed to do integration by parts twice, but it keeps working out to 0=0 or sin(t)=sin(t). How am I supposed to approach it? integral

You can view more similar questions or ask a new question.