Bomai places 7 mol of ammonia in a 14L flask. At equilibrium 0.2M ammonium was found in the flask.
1.what is the balanced chemical reaction for the above reaction?
2.what is the equilibrium constant kc for this reaction?
3.what are the conjugate acid and base for the above reaction?
1. The balanced chemical reaction for the above reaction is:
NH3 (g) ⇌ NH4+ (aq)
2. The equilibrium constant Kc for this reaction can be calculated using the equation:
Kc = [NH4+] / [NH3]
Given that the concentration of NH4+ at equilibrium is 0.2 M, and the original concentration of NH3 was (7 mol / 14 L) = 0.5 M, we can plug these values into the equation:
Kc = 0.2 / 0.5 = 0.4
Therefore, the equilibrium constant Kc for this reaction is 0.4.
3. The conjugate acid of NH3 is NH4+, and the conjugate base of NH4+ is NH3.