Based on the data provided, there don't appear to be any significant outliers. All values fall within a reasonable range and there are no extreme values that would significantly skew the data.
d. which is the better way to represent the central tendancy of this data- mean or median
In this case, the median may be a better way to represent the central tendency of the data because there are a few values at the extremes (e.g. 3.5 and 52.5) that could be considered outliers and would have a greater impact on the mean than the median. The median is less affected by outliers and provides a more robust measure of central tendency in such cases.