Inside a hat are cards with the letters A, M, O, L, and S written on them, one letter per card. A card is picked twice. If the card is replaced before picking another card, what is the probability that the first card is a consonant, and the second card is a vowel?(1 point)
Responses
15
Start Fraction 1 over 5 End Fraction
35
Start Fraction 3 over 5 End Fraction
725
Start Fraction 7 over 25 End Fraction
625
To find the probability of the first card being a consonant and the second card being a vowel, we first need to determine the total number of possible outcomes.
There are 5 letters on the cards (A, M, O, L, S), so the total number of outcomes when picking a card twice with replacement is 5 x 5 = 25.
Next, we need to determine the number of outcomes where the first card is a consonant (M, L, S) and the second card is a vowel (A, O).
There are 3 consonants and 2 vowels, so the number of outcomes where the first card is a consonant and the second card is a vowel is 3 x 2 = 6.
Therefore, the probability is the number of successful outcomes (6) divided by the total number of outcomes (25), which is 6/25, or 6/25.
Therefore, the answer is:
Start Fraction 6 over 25 End Fraction