Plugging in the values, we get:
P(X = 6) = (10 choose 6) * (1/4)^6 * (3/4)^(10-6)
P(X = 6) = (10 choose 6) * (1/4)^6 * (3/4)^(10-6)
P(X = 6) = (10 choose 6) * (1/4)^6 * (3/4)^4
P(X = 6) = (210) * (1/4096) * (81/256)
P(X = 6) = 0.23627
Therefore, the probability of getting exactly 6 heads in 10 coin flips is approximately 0.23627.