Which of the following is a point on the graph as described by the function y = (2x + 1) ^ 2 - 4 (1 point)
Ο (- 1, - 5)
Ο (0, - 2)
Ο (1, 2)
Ο (- 1, - 3)
Let's plug in the x-values from each point and see which one is on the graph:
1. For point (-1, -5): y = (2(-1) + 1)^2 - 4 = (2 - 1)^2 - 4 = (1)^2 - 4 = 1 - 4 = -3 ≠ -5
2. For point (0, -2): y = (2(0) + 1)^2 - 4 = (0 + 1)^2 - 4 = (1)^2 - 4 = 1 - 4 = -3 ≠ -2
3. For point (1, 2): y = (2(1) + 1)^2 - 4 = (2 + 1)^2 - 4 = (3)^2 - 4 = 9 - 4 = 5 ≠ 2
4. For point (-1, -3): y = (2(-1) + 1)^2 - 4 = ( -2 + 1)^2 - 4 = (-1)^2 - 4 = 1 - 4 = -3
Therefore, the point on the graph of the function y = (2x + 1)^2 - 4 is (-1, -3).