The low temperatures during one week in January were 2, -3, -9, -11, 1, -8 and -9. What was the median low temperature that week?
To find the median low temperature, we first need to arrange the temperatures in ascending order:
-11, -9, -9, -8, -3, 1, 2
Since there are an odd number of temperatures (7), the median is the middle number, which in this case is -8.
Therefore, the median low temperature that week was -8.
The stem-and-leaf plot shows the ages of a group of friends. Find the median age.
stem leaf
2 8
3 1 2 4
4 2 7 9
5 4
key: 2l8= 28 years
To find the median age:
1. Write the ages in ascending order:
28, 31, 32, 34, 42, 47, 49, 54
2. Since there are 8 ages listed, the median will be the average of the 4th and 5th ages.
Therefore, the median age is (34 + 42) / 2 = 38.
So, the median age of the group of friends is 38 years.
Here are the math test scores of 10 randomly selected students from class 1 and class 2.
class 1: 75 l 80 l 84 l 79 l 92 l 86 l 88 l 86 l 86 l 90 l
class 2: 83 l 85 l 91 l 93 l 72 l 85 l 76 l 80 l 82 l 89 l
Find the mean scores of each sample. Based on the mean, which class generally performed better on the math test?
- The mean scores for class 1 is (?). The mean school for class 2 is (?). Based on the mean, class (?) generally performed better on the math test.
To find the mean scores for each class:
For class 1:
(75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10 = 856 / 10 = 85.6
For class 2:
(83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10 = 856 / 10 = 82.6
Therefore, the mean score for class 1 is 85.6 and for class 2 is 82.6.
Based on the mean scores, class 1 generally performed better on the math test as it has a higher mean score.
class one is not 85.6 and class two is not 82.6. It said those are wrong.
I apologize, let's re-calculate the mean scores for each class.
For class 1:
(75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10 = 850 / 10 = 85
For class 2:
(83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10 = 846 / 10 = 84.6
Therefore, the mean score for class 1 is 85 and for class 2 is 84.6.
Based on the mean scores, class 1 generally performed better on the math test as it has a higher mean score.
still wrong
I apologize for the mistake. Let's recalculate the mean scores for each class.
For class 1:
(75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90) / 10 = 846 / 10 = 84.6
For class 2:
(83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89) / 10 = 846 / 10 = 84.6
Therefore, the mean score for class 1 is 84.6 and for class 2 is 84.6.
Based on the mean scores, both classes performed equally well on the math test with the same mean score of 84.6.