What is the area of the sector of a circle with θ=122°
and a diameter of 18 inches? Write your answer to two decimal places.(1 point)
A=
π in.2
A= (122/360) * π * (9)^2
A= (0.3389) * π * 81
A= 27.28 in^2
Therefore, the area of the sector of a circle with θ=122° and a diameter of 18 inches is 27.28 in^2.