An urgent care center has two campuses, A and B. The doctors at the two campuses are comparing the wait time in minutes for customers. The amount of time was measured for each patient at both campuses. The results are provided in the table below.
Campus A Campus B
9
24
15
11
21
14
19
13
30
22
31
5
16
11
27
17
19
21
7
17
22
26
28
24
21
18
4
37
33
8
Justify the measure of center and measure of spread that could be used to compare the two data sets.
(1 point)
Responses
The median and interquartile range could be used. Although there are no outliers, the distribution for Campus A is skewed left, and the distribution for Campus B is skewed right.
The median and interquartile range could be used. Although there are no outliers, the distribution for Campus A is skewed left, and the distribution for Campus B is skewed right.
The mean and standard deviation could be used because both of the distributions are roughly symmetric, and they do not have outliers.
The mean and standard deviation could be used because both of the distributions are roughly symmetric, and they do not have outliers.
The median and interquartile range could be used because the distribution for Campus A is skewed right with an outlier of 30
minutes, and the distribution for Campus B is roughly symmetric with no outliers.
The median and interquartile range could be used because the distribution for Campus A is skewed right with an outlier of 30 minutes, and the distribution for Campus B is roughly symmetric with no outliers.
The mean and standard deviation could be used. Both of the distributions are roughly symmetric, and only Campus B has an outlier of 37
minutes.
The mean and standard deviation could be used. Both of the distributions are roughly symmetric, and only Campus B has an outlier of 37 minutes.
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