1. 30x + 50y = 400
2. x + y = 10
To solve this system of equations, we can use the substitution method or the elimination method.
Substitution method:
From equation 2, we can rearrange it to get x = 10 - y.
Substitute the expression for x into equation 1:
30(10 - y) + 50y = 400
300 - 30y + 50y = 400
20y = 100
y = 5
Now, substitute y = 5 back into x = 10 - y:
x = 10 - 5
x = 5
Therefore, the solution to the system of equations is x = 5, y = 5.