(5y+2)(2y^2+y−4)

To distribute, multiply each term in the first binomial by each term in the second binomial:

= 5y(2y^2) + 5y(y) + 5y(-4) + 2(2y^2) + 2(y) + 2(-4)
= 10y^3 + 5y^2 - 20y + 4y^2 + 2y - 8
= 10y^3 + 9y^2 - 18y - 8

Therefore, (5y+2)(2y^2+y−4) simplifies to 10y^3 + 9y^2 - 18y - 8.