(4y−3)(8y^2−8y−5)

To find the product of (4y−3)(8y^2−8y−5), we will use the distributive property.

First, we will distribute 4y to each term in the second parenthesis:

4y * 8y^2 = 32y^3
4y * -8y = -32y^2
4y * -5 = -20y

Next, we will distribute -3 to each term in the second parenthesis:

-3 * 8y^2 = -24y^2
-3 * -8y = 24y
-3 * -5 = 15

Now we will combine like terms:

32y^3 - 32y^2 - 20y - 24y^2 + 24y + 15

Combining like terms, we get:

32y^3 - 56y^2 + 4y + 15

Therefore, the product of (4y−3)(8y^2−8y−5) is 32y^3 - 56y^2 + 4y + 15.