(2y+3)(3y+5)
Expanding this expression using the distributive property, we get:
(2y + 3)(3y + 5) = 2y * 3y + 2y * 5 + 3 * 3y + 3 * 5
= 6y^2 + 10y + 9y + 15
= 6y^2 + 19y + 15
So, (2y + 3)(3y + 5) is equal to 6y^2 + 19y + 15.