A 22.0-mal sample of 12M H2SO4 is diluted to a volume of 1200.0 mL. What is the molarity of the diluted solution?

To find the molarity of the diluted solution, we can use the formula:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Given:
- M1 = 12M
- V1 = 22.0 mL = 0.0220 L
- V2 = 1200.0 mL = 1.200 L

Plugging in the values:

(12M)(0.0220L) = M2(1.200L)
0.264 = 1.200M2

Now, solve for M2:
M2 = 0.264 / 1.200
M2 = 0.22 M

Therefore, the molarity of the diluted solution is 0.22 M.