How would you correctly prepare 125 mL of a 0.30M solution of copper(II) sulfate (CuSO4) from a 2.00M solution of CuSO4?
To prepare 125 mL of a 0.30M solution of copper(II) sulfate (CuSO4) from a 2.00M solution of CuSO4, you can use the dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration of CuSO4 (2.00M)
V1 = volume of initial CuSO4 solution needed
C2 = final concentration of CuSO4 (0.30M)
V2 = final volume of CuSO4 solution to be prepared (125 mL)
Now plug in the values and solve for V1:
(2.00M)(V1) = (0.30M)(125mL)
2V1 = 37.5
V1 = 37.5 / 2
V1 = 18.75 mL
So you would need 18.75 mL of the 2.00M CuSO4 solution to prepare 125 mL of a 0.30M CuSO4 solution. You would then add water to make up the remaining volume to reach 125 mL.