Three resistors are linked in parallel, as depicted in the provided diagram.
A voltage of 30.0 V is connected to three resistors, each 10.0 Ohms. There is an arrow pointing next to the third resistor.
Applying the formula, what should be the measurement displayed on an ammeter positioned at the location indicated by the arrow?
Voltage = Current × Resistance
First, we need to calculate the total resistance of the parallel circuit.
1/R_total = 1/R1 + 1/R2 + 1/R3
1/R_total = 1/10 + 1/10 + 1/10
1/R_total = 3/10
R_total = 10/3 = 3.33 Ohms
Now, we can use Ohm's Law to find the total current flowing through the circuit.
Voltage = Current × Resistance
30.0 = Current × 3.33
Current = 30.0 / 3.33
Current = 9.01 A
Therefore, the ammeter should display a current of 9.01 A at the location indicated by the arrow.