A wood salesperson has a fenced area in which they keep all their wood to keep it
organized. The area itself is 12 ft. long and 8 ft. wide. The fence is 8 ft. high. They
have bigger pieces of wood that are 4 ft. long and 2 ft. wide and smaller pieces of wood
that are 2 ft. long and 1 ft. wide. Each piece of wood is 6 in., or ½ ft., tall.
2. If the salesperson put all big pieces of wood in the fenced area, what is the most
that they could fit?
First, we need to calculate the area of each big piece of wood:
Big piece of wood area = length x width x height
Big piece of wood area = 4 ft x 2 ft x 0.5 ft
Big piece of wood area = 4 ft x 2 ft x 0.5 ft
Big piece of wood area = 4 ft x 1 ft
Big piece of wood area = 8 ft²
Next, we need to calculate the total area of the fenced area:
Fenced area = length x width
Fenced area = 12 ft x 8 ft
Fenced area = 96 ft²
Then, we can calculate the maximum number of big pieces of wood that can fit in the fenced area:
Maximum number of big pieces of wood = Fenced area / Big piece of wood area
Maximum number of big pieces of wood = 96 ft² / 8 ft²
Maximum number of big pieces of wood = 12
Therefore, the most big pieces of wood that the salesperson could fit in the fenced area is 12.