what mass of silver was heated if its temperature rises from 21.0 C to 51.0 C as a result of absorbing 3.50 kJ of energy
To solve this problem, we can use the equation:
q = mcΔT
Where:
- q is the heat absorbed by the substance (in this case, 3.50 kJ or 3500 J),
- m is the mass of the substance we want to find,
- c is the specific heat capacity of the substance (for silver, it is 0.235 J/g°C),
- ΔT is the change in temperature (final temperature - initial temperature, in this case, (51.0 - 21.0) = 30.0 °C).
Rearranging the equation, we have:
m = q / (c * ΔT)
Substituting the values, we get:
m = 3500 J / (0.235 J/g°C * 30.0 °C)
Now let's calculate the mass:
m ≈ 52.35 g
Therefore, the mass of silver that was heated is approximately 52.35 grams.