Calculate the molality of aqueous solution of sulfuric acid by the following data
Molarity =18
Molar mass =98
Density =1.84 g/cm3
First, we need to calculate the molality of the sulfuric acid solution using the formula:
Molality (m) = (Molarity * Molar Mass) / (1000 * Density)
Given data:
Molarity = 18 M
Molar Mass = 98 g/mol
Density = 1.84 g/cm^3
Converting density to g/mL:
Density = 1.84 g/cm^3 = 1.84 g/mL
Now, plug the values into the formula:
Molality (m) = (18 * 98) / (1000 * 1.84)
Molality (m) = (1764) / (1840)
Molality (m) = 0.96 mol/kg
Therefore, the molality of the aqueous solution of sulfuric acid is 0.96 mol/kg.