Findtheequationoftheaxisofsymmetryfortheparabolay = –5x2 − 2x.
Simplify any numbers and write them as proper fractions, improper fractions, or integers.
To find the equation of the axis of symmetry for the parabola, we use the formula x = -b/2a where the equation of the parabola is in the form y = ax^2 + bx + c.
In this case, the equation is y = -5x^2 - 2x.
So, a = -5 and b = -2.
Now, we can find the x-coordinate of the vertex by using x = -(-2) / (2*(-5)) = 2 / -10 = -1/5.
Therefore, the equation of the axis of symmetry is x = -1/5.