solve a spiral spring has a length of 14cm when a force of 4n is hung on it a force of 6n extends the spring by 4cm calculate the unstretched length of the spring
Let the unstretched length of the spring be represented by L.
According to Hooke's Law, the extension of a spring is directly proportional to the applied force. Therefore, we can use the formula:
F = kx
Where:
F = Force applied (N),
k = Spring constant,
x = Extension of the spring (m).
For the first scenario:
4N = k(0.14m)
k = 4N / 0.14m
k = 28.57 N/m
For the second scenario:
6N = 28.57 N/m * (0.14m + 0.04m)
6N = 28.57 N/m * 0.18m
m = 6N / 5.14 N/m
m = 0.21m
Therefore, the unstretched length of the spring is:
L = 0.14m - 0.21m
L = 0.07m
L = 7cm
So, the unstretched length of the spring is 7cm.