What is the distance between (19, -6) and (8, -6) on a coordinate plane?
The distance between the two points can be found using the distance formula:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the points are (19, -6) and (8, -6), so x1 = 19, y1 = -6, x2 = 8, and y2 = -6.
Plugging these values into the formula:
distance = √((8 - 19)^2 + (-6 - (-6))^2)
distance = √((-11)^2 + (0)^2)
distance = √(121 + 0)
distance = √121
distance = 11
Therefore, the distance between (19, -6) and (8, -6) is 11 units.