Question A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn without replacement. Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth.(1 point)
There are a total of 52 cards in the deck and 13 of them are diamonds.
To calculate the probability of drawing two diamond cards, we first need to find the probability of drawing one diamond card and then drawing another diamond card.
The probability of drawing the first diamond card is 13/52 = 1/4.
After drawing one diamond card, there are now only 12 diamond cards left in the deck and a total of 51 cards remaining.
So, the probability of drawing a second diamond card is 12/51.
To find the probability of drawing two diamond cards, we multiply the probabilities of the individual events:
(1/4) * (12/51) = 3/51 = 1/17 ≈ 0.0588
Converting this to percent form, we get 5.88%.
Therefore, the probability of drawing two diamond cards is 5.88%.