Find the vertex of the function
f(x) = 3x^2 - 6x + 4
To find the vertex of the function, we can use the formula for the x-coordinate of the vertex of a parabola in the form of y = ax^2 + bx + c:
x = -b / 2a
In this case, a = 3 and b = -6.
Plugging these values into the formula, we get:
x = -(-6) / 2(3)
x = 6 / 6
x = 1
Now that we have the x-coordinate of the vertex, we can find the y-coordinate by plugging x = 1 back into the original function:
f(1) = 3(1)^2 - 6(1) + 4
f(1) = 3 - 6 + 4
f(1) = 1
Therefore, the vertex of the function f(x) = 3x^2 - 6x + 4 is (1, 1).