Question 8
You have sampled a population in which you know that the percentage of the homozygous dominant genotype (AA) is 16%.
Using that 16%, calculate the following - the frequency of the "A" allele. (p)
p2 + 2pq + q2 = 1 and p + q = 1
a
0.16
b
0.36
c
1
d
0.4
The percentage of the homozygous dominant genotype (AA) is 16%, which means p^2 = 0.16. Therefore, p = sqrt(0.16) = 0.4.
So, the frequency of the "A" allele (p) is 0.4.
Correct answer: d) 0.4