What is the [H +] of vinegar if the pH is 2.1
[H +] = 10^(-pH)
[H +] = 10^(-2.1)
[H +] = 7.94 x 10^(-3) M
The [H +] of vinegar with a pH of 2.1 is 7.94 x 10^(-3) M.
[H +] = 10^(-2.1)
[H +] = 7.94 x 10^(-3) M
The [H +] of vinegar with a pH of 2.1 is 7.94 x 10^(-3) M.