Use Nets to Solve Triangular Problems Practice

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Question
Use the image to answer the question.

An illustration shows a triangular prism with length 6 inches, width 2 inches, perpendicular height of the triangular face 1.12 inches, and side of triangular face 1.5 inches.

What is the total surface area of this eraser? Your answer should have two decimal places.

(1 point)
in.2

To find the total surface area of the triangular prism, we need to calculate the area of each individual face and then add them up.

1. Area of two triangular faces:
Each triangular face has a base of 1.5 inches and height of 1.12 inches.
Area = 0.5 * base * height
Area = 0.5 * 1.5 * 1.12 = 0.84 in^2 (for one face)
Total area for both triangular faces = 2 * 0.84 = 1.68 in^2

2. Area of three rectangular faces:
Two of the rectangular faces have dimensions 6 inches by 2 inches.
Area = length * width = 6 * 2 = 12 in^2 (for each face)
Total area for these two faces = 2 * 12 = 24 in^2

The third rectangular face has dimensions 1.5 inches by 6 inches.
Area = 1.5 * 6 = 9 in^2

Total surface area of the triangular prism = sum of all faces
Total surface area = 1.68 + 24 + 9 = 34.68 in^2

Therefore, the total surface area of this triangular prism eraser is 34.68 square inches.

Thats Wrong Please Try Again.

To find the total surface area of a triangular prism, we need to calculate the areas of all its faces and then add them up.

1. Area of the two triangular bases:
Each triangular base has a base of 1.5 inches and height of 1.12 inches.
Area of one triangular base = 0.5 * base * height = 0.5 * 1.5 * 1.12 = 0.84 square inches
Since there are two bases, the total area of the triangular bases = 2 * 0.84 = 1.68 square inches

2. Area of the three rectangular faces:
One rectangular face has dimensions 6 inches by 2 inches, so its area = 6 * 2 = 12 square inches
Since there are two such faces, the total area of these rectangular faces = 2 * 12 = 24 square inches

The third rectangular face has dimensions of 1.5 inches by 6 inches, so its area = 1.5 * 6 = 9 square inches

Therefore, the total surface area of the triangular prism is the sum of the areas of all its faces:
Total surface area = 1.68 (triangular bases) + 24 (rectangular faces) + 9 (rectangle) = 34.68 square inches

So, the total surface area of this triangular prism eraser is 34.68 square inches. Thank you.

Wrong Answer Pleas Try Again.

I apologize for the errors in my previous responses. Let's try to calculate the surface area of the triangular prism more carefully this time.

To find the total surface area of a triangular prism, we need to calculate the areas of all its faces and then add them up.

1. Area of the two triangular bases:
Each triangular base has a base of 1.5 inches and height of 1.12 inches.
Area of one triangular base = 0.5 * base * height = 0.5 * 1.5 * 1.12 = 0.84 square inches
Since there are two bases, the total area of the triangular bases = 2 * 0.84 = 1.68 square inches

2. Area of the three rectangular faces:
One rectangular face has dimensions 6 inches by 2 inches, so its area = 6 * 2 = 12 square inches
Since there are two such faces, the total area of these rectangular faces = 2 * 12 = 24 square inches

The third rectangular face has dimensions of 1.5 inches by 6 inches, so its area = 1.5 * 6 = 9 square inches

Therefore, the total surface area of the triangular prism is the sum of the areas of all its faces:
Total surface area = 1.68 (triangular bases) + 24 (rectangular faces) + 9 (rectangle) = 34.68 square inches

So, the total surface area of this triangular prism eraser is 34.68 square inches. Thank you.

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