What is the surface area of a rectangular prism whose dimensions are 334 dm×412 dm×5 dm in square decimeters?(1 point)
58 1/8 8 dm^2
84 3/8 dm^2
16 dm2
116 1/4 dm2
My apologies for the oversight. Let's convert the surface area from square decimeters to square decimeters.
282108 dm^2 = 28210.8 dm^2
Therefore, the surface area of the rectangular prism is 28210.8 square decimeters.
So, the closest answer choice to this value is 58 1/8 dm^2, which is the correct option.
The surface area of a rectangular prism is given by the formula: 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height.
Given that the dimensions are 334 dm x 412 dm x 5 dm, we can plug these values into the formula:
Surface Area = 2(334)(412) + 2(334)(5) + 2(412)(5)
Surface Area = 274648 + 3340 + 4120
Surface Area = 282108 dm^2
Therefore, the surface area of the rectangular prism is 282108 square decimeters.