If 98 out of 200 individuals in a population express the recessive phenotype, what percent of the population would you predict to be heterozygous?
a
70%
b
30%
c
42%
d
49%
The recessive phenotype is expressed in individuals who are homozygous recessive (rr) or heterozygous (Rr). Given that 98 individuals express the recessive phenotype, and assuming the total population is 200, the number of individuals that express the recessive phenotype and are homozygous recessive (rr) would be 2 (since 98 are recessive and we know that the total is 200, so the number of individuals that do not express the recessive phenotype would be 200-98=102).
Hence, the number of individuals that express the recessive phenotype and are heterozygous (Rr) would be 98 - 2 = 96.
The total number of heterozygous individuals would be 96, so the percentage of heterozygous individuals in the population would be (96/200) * 100% = 48%.
Therefore, the closest option is d) 49%.