Surface Area of Triangular Prisms Practice

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Question
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An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as a rectangle, a square, and another rectangle joined horizontally next to each other. The width of the two rectangles and the side of the square measure 3 centimeters. The length of the left rectangle is 4 centimeters. The side of the middle square, drawn in a dashed line, is 3 centimeters. The length of the right rectangle is 5 centimeters. Two right triangles adjoin the middle square at the top and bottom, with each perpendicular side measuring 4 centimeters and each hypotenuse measuring 5 centimeters.

What is the surface area of the shown net for a triangular prism?

(1 point)
cm2

To find the surface area of the triangular prism, we need to find the area of each of the individual shapes in the net and then add them together.

1. The area of the left rectangle: 4 cm (length) x 3 cm (width) = 12 cm^2
2. The area of the middle square: 3 cm x 3 cm = 9 cm^2
3. The area of the right rectangle: 5 cm (length) x 3 cm (width) = 15 cm^2
4. The area of the two right triangles: 2 x (1/2 x 4 cm x 3 cm) = 12 cm^2

Adding all the areas together:
12 cm^2 + 9 cm^2 + 15 cm^2 + 12 cm^2 = 48 cm^2

The surface area of the shown net for a triangular prism is 48 cm^2.