Trend Lines Practice
Complete this assessment to review what you've learned. It will not count toward your grade.
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Question
Use the image to answer the question.
An illustration of a scatterplot graph shows x-axis ranging from 0 to 10 in increments of 1 and y-axis ranging from 0 to 30 in increments of 2. Multiple points are plotted around a line that points upward to the right with an arrowhead on the bottom.
The line passes approximately through left parenthesis 0 comma 12 right parenthesis, left parenthesis 4 comma 16 right parenthesis, and left parenthesis 6 comma 18 right parenthesis. 12 points are plotted close to the line.
Write an equation in slope-intercept form of the trend line.
(1 point)
y=
2x+10
wrong
I apologize for the mistake. Let's calculate the equation of the trend line based on the given points.
We have the points (0, 12), (4, 16), and (6, 18).
First, let's calculate the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
m = (16 - 12) / (4 - 0)
m = 4 / 4
m = 1
Now that we have the slope, we can use the point-slope form of the equation of a line:
y - y1 = m(x - x1)
Choosing the point (0, 12):
y - 12 = 1(x - 0)
y - 12 = x
y = x + 12
Therefore, the equation of the trend line in slope-intercept form is:
y = x + 12