Surface Area of Cylinders Practice
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Question
Use the image to answer the question.
An illustration shows a rectangle of unknown height with a circle of radius 3 feet attached to its top left and a circle of radius 3 feet attached to its bottom right.
If the surface area of the net diagram of the right circular cylinder is 395.64 feet2, find the height of the net diagram. Use 3.14 for π.
(1 point)
feet
To find the surface area of the net diagram, we need to find the area of the rectangle and the areas of the two circles.
Let's denote the height of the rectangle as h.
The area of the rectangle is given by h * 3 (since the base of the rectangle is the diameter of the circle, which is 2 times the radius of 3 feet).
The area of each circle is πr^2, so the area of both circles combined is 2(3.14 * 3^2).
Adding all these areas together should give us the surface area of the net diagram, which is 395.64 feet^2:
h * 3 + 2(3.14 * 3^2) = 395.64
h * 3 + 2(3.14 * 9) = 395.64
h * 3 + 2(28.26) = 395.64
h * 3 + 56.52 = 395.64
h * 3 = 339.12
h = 113.04 feet
Therefore, the height of the net diagram is 113.04 feet.