Surface Area of Cylinders Practice
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Question
Use the image to answer the question.
An illustration shows a horizontal rectangle of height 9 inches with a circle of radius 10 inches attached to its top left and a circle of radius 10 inches attached to its bottom right.
Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π .
(1 point)
inches2
To find the surface area of the net diagram of the right circular cylinder, we need to find the areas of the two circles and the rectangular side.
The area of a circle is πr^2, and since we are given that the radius is 10 inches, the area of each circle is 3.14 x 10^2 = 3.14 x 100 = 314 square inches.
The area of the rectangle is the base (which is the circumference of the circle, 2πr) multiplied by the height. The base is 2(3.14)(10) = 62.8 inches, and the height is 9 inches, so the area of the rectangle is 62.8 x 9 = 565.2 square inches.
Therefore, the total surface area of the net diagram of the right circular cylinder is 2(314) + 565.2 = 628 + 565.2 = 1193.2 square inches.