A jeepney from rest
accelerates uniformly over a time of 3.25 seconds and covers a distance of 15
meters. What is the given initial velocity?
To find the initial velocity of the jeepney, we can use the formula for uniformly accelerated motion:
distance = (initial velocity * time) + (0.5 * acceleration * time^2)
Since the jeepney starts from rest, its initial velocity is 0 m/s. Therefore, the formula simplifies to:
distance = 0.5 * acceleration * time^2
Plugging in the given values:
15 meters = 0.5 * acceleration * (3.25 seconds)^2
Solving for acceleration:
acceleration = (15 meters) / (0.5 * (3.25 seconds)^2)
acceleration ≈ 2.77 m/s^2
We can now calculate the initial velocity using the formula:
initial velocity = (distance - 0.5 * acceleration * time^2) / time
initial velocity = (15 meters - 0.5 * 2.77 m/s^2 * (3.25 seconds)^2) / 3.25 seconds
initial velocity ≈ 1.89 m/s
Therefore, the given initial velocity of the jeepney is approximately 1.89 m/s.