Graph the quadratic functions

y = -2x^2 and y = -2x^2 + 4
on a separate piece of paper. Using those graphs, compare and contrast the shape and position of the graphs

The graphs of the two quadratic functions y = -2x^2 and y = -2x^2 + 4 are both downward-facing parabolas. However, the second function y = -2x^2 + 4 is shifted upward by 4 units compared to y = -2x^2. This shift essentially raises the entire graph of y = -2x^2 by 4 units.

Additionally, since the coefficient of x^2 in both functions is negative (-2), the graphs open downwards. The vertex of both parabolas is located at the point (0, 0) for y = -2x^2 and at (0, 4) for y = -2x^2 + 4. The vertex represents the maximum point of the parabola when the coefficient of x^2 is negative.

The graphs have the same shape and concavity, but the second graph is shifted vertically upwards from the first one. This shift changes the y-intercept of the second graph to (0, 4) compared to the y-intercept of the first graph, which is at the origin (0, 0).

In summary, the two graphs have the same concave shape but differ in their vertical positions due to the constant added to the second function.

now use simple wording

The graphs of y = -2x^2 and y = -2x^2 + 4 are both downward curves, like frowns. The second graph is shifted up by 4 units compared to the first graph. Both graphs have the same shape but are positioned differently on the graph. The vertex of the first graph is at (0, 0) and the vertex of the second graph is at (0, 4). The second graph starts higher up than the first graph but still has the same curve.

pls make shorter

Both graphs are downward curves, but the second one is shifted up by 4 units. They have the same shape, but the second graph starts higher on the y-axis.