Solve the following problem using cross-multiplication. Ja’Quin draws a picture of a horse that measures 7 inches by 4 inches. He increases the size of the picture on a photocopier so that its new width is 6 inches. What is the new length of the picture? Round to the nearest tenth.(1 point)
To find the new length of the picture, we can set up a proportion using the cross-multiplication method.
Original width: 7 inches
Original length: 4 inches
New width: 6 inches
New length: x inches
7/4 = 6/x
Cross-multiplying:
7x = 24
Divide both sides by 7:
x = 24/7 ≈ 3.4 inches
So, the new length of the picture is approximately 3.4 inches.
wrong bud
Apologies for the mistake. Let's correct the calculation:
Original width: 7 inches
Original length: 4 inches
New width: 6 inches
New length: x inches
Using the cross-multiplication method:
7/4 = 6/x
Cross-multiplying:
7x = 4 * 6
7x = 24
Now, divide both sides by 7:
x = 24 / 7
x ≈ 3.4 inches
Therefore, the new length of the picture is approximately 3.4 inches.
use one of the following: 1.5, 1.2, 10.5, 42.0
To find the new length of the picture, we can set up a proportion using the cross-multiplication method.
Original width: 7 inches
Original length: 4 inches
New width: 6 inches
New length: x inches
7/4 = 6/x
Cross-multiply:
7x = 24
Solve for x:
x = 24/7
x ≈ 3.4
Therefore, the new length of the picture is approximately 3.4 inches. Round to the nearest tenth gives 3.4 as the final answer.