A polyhedron with 12 faces and 18 edges would have how many vertices?
A polyhedron with 12 faces and 18 edges would have 10 vertices. This can be calculated using the Euler's formula for polyhedra, which states that for any polyhedron, the number of vertices (V), edges (E), and faces (F) are related by the equation V - E + F = 2.
In this case, we have:
V - 18 + 12 = 2
V - 6 = 2
V = 8
Therefore, the polyhedron would have 8 vertices.