The dimensions of rectangle A are three times the dimensions of rectangle B. The area of rectangle A is 882 cm2.
What is the area of rectangle B?
A.
49 cm2
B.
98 cm2
C.
294 cm2
D.
196 cm2
C. 294 cm2
Since the dimensions of rectangle A are three times the dimensions of rectangle B, if we let the dimensions of rectangle B be x and y, the dimensions of rectangle A would be 3x and 3y.
Given that the area of rectangle A is 882 cm2, we can set up the equation:
3x * 3y = 882
9xy = 882
xy = 882/9
xy = 98
Therefore, the area of rectangle B is 98 cm2.