A chemist combines 45g of NH₃ with HCl to form 70g of NH₄Cl. What is the possible mass of HCl used in this reaction? * 45g HCl 25g HCl 115g HCl
The balanced chemical equation for the reaction between NH₃ and HCl to form NH₄Cl is:
NH₃ + HCl -> NH₄Cl
From the reaction equation, it is clear that 1 mole of NH₃ reacts with 1 mole of HCl to form 1 mole of NH₄Cl.
Step 1: Calculate moles of NH₃ used:
Molar mass of NH₃ = 17.03 + 3(1.01) = 17.03 + 3.03 = 20.01 g/mol
Moles of NH₃ = 45g / 20.01 g/mol = 2.25 mol
Step 2: Calculate moles of NH₄Cl formed:
Molar mass of NH₄Cl = 14.01 + 4(1.01) + 35.45 = 14.01 + 4.04 + 35.45 = 53.50 g/mol
Moles of NH₄Cl formed = 70g / 53.50 g/mol = 1.31 mol
Since the reaction is 1:1 ratio between NH₃ and HCl, the moles of NH₃ reacting will be the same as the moles of HCl used.
Step 3: Calculate mass of HCl used:
Molar mass of HCl = 1.01 + 35.45 = 36.46 g/mol
Mass of HCl used = 36.46 g/mol x 2.25 mol = 82.04g
Therefore, the possible mass of HCl used in this reaction is 82.04g. So none of the given options are correct.