Algebra

k) If the trip is 3 miles, how much does each one charge? If the trip is 6 miles, how much does each one charge? Explain

8(3)+32=y
24+32=y
Y=56

10(3)+24=y
30+24=54
Y=54

8(6)+32=y
48+32=y
Y=80

10(6)+24=y
60+24=84
Y=84

THIS IS WHAT I CAN'T FIGURE OUT :-)-->
At what mileage are both services charging the same rate? Explain.

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  1. 8(m)+32=10(m)+24
    solve for m.
    subtract 8 m from each side
    subtract 24 from each side.

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