What are the coordinates of the focus of the parabola?
y=−0.25x2+6
The focus of a parabola is (h, k+1/4a), where the equation of the parabola is of the form y = ax^2 + bx + c.
In this case, the equation of the parabola y = -0.25x^2 + 6 is in the form y = ax^2 + bx + c.
Therefore, a = -0.25, b = 0, and c = 6.
The focus of the parabola is therefore (h, k + 1/4a) = (0, 6 + 1/4*(-0.25)) = (0, 6.0625).
Therefore, the coordinates of the focus of the parabola are (0, 6.0625).