Joel was studying the function f(x) = 2x^2– 6x + 4. He concluded that its graph would have an axis of symmetry of y=-0.5, a vertex of (1.5,-0.5), zeros of x=1 and x=3, and a y-intercept of (0,4). What were his errors? (select all that apply)
The graph does not have an axis of symmetry of y=-0.5
The graph does not have a zero of x=3
The graph does not have a y-intercept of (0,4)
The graph does not have a zero of x=1
The graph does not have a vertex of (1.5,-0.5)
only
The graph does not have an axis of symmetry of y=-0.5
The graph does not have a zero of x=3
the vertex is indeed at (1.5,-0.5)
and it has a zero of x=1, since f(x) = 2(x-1)(x-2)
You are correct. I apologize for the oversight. Thank you for pointing out the errors. The correct errors are:
- The graph does not have an axis of symmetry of y= -0.5
- The graph does not have a zero of x= 3
The errors are:
- The graph does not have an axis of symmetry of y=-0.5
- The graph does not have a vertex of (1.5,-0.5)
- The graph does not have a zero of x=1