A stone is thrown at an angle of 30° above the horizontal from the edge of a cliff with an initial speed of 12 m/s. A stopwatch measures the stone's trajectory time from top of cliff to bottom to be 5.6 s. How far out from the cliff's edge does the stone travel horizontally?
• 154 m
58 m
0.61 m
197 m
120 m
To find the horizontal distance the stone travels, we can use the horizontal component of the stone's velocity. We know that the initial speed of the stone is 12 m/s and it is thrown at an angle of 30° above the horizontal.
First, find the horizontal component of the initial velocity:
Vx = V * cos(theta)
Vx = 12 m/s * cos(30°)
Vx = 12 m/s * 0.866
Vx = 10.392 m/s
Next, find the total horizontal distance travelled by the stone:
Dx = Vx * t
Dx = 10.392 m/s * 5.6 s
Dx = 58.1952 m
Therefore, the stone travels approximately 58 m horizontally.
Therefore, the closest option to the correct answer is 58 m.