Write an equation in slope intercept form of the trend line.y intercept=20. X intercept=(15,40)
First, let's find the slope using the given points (15,40) and the y-intercept (0,20).
Slope (m) = (y2 - y1) / (x2 - x1)
Slope = (40 - 20) / (15 - 0)
Slope = 20 / 15
Slope = 4/3
Now we have the slope and the y-intercept, we can plug them into the slope-intercept form of the equation:
y = mx + b
where:
m = slope = 4/3
b = y-intercept = 20
Therefore, the equation of the trend line in slope-intercept form is:
y = (4/3)x + 20