Trend line passes thru (4,16) what is slope intercept equation
To find the slope-intercept equation of a line passing through a given point (4,16), we need to determine the slope of the line first.
Let's assume the equation of the line is y = mx + b, where m is the slope and b is the y-intercept.
Given point: (4,16)
This means the x-coordinate is 4 and the y-coordinate is 16.
Now, we need to calculate the slope using the given point and the point (0,b). We can choose b=0 for simplicity.
Using the formula for slope: m = (y2 - y1) / (x2 - x1), where (x1,y1) = (4,16) and (x2,y2) = (0,b).
m = (b - 16) / (0 - 4)
m = (b - 16) / -4
4m = 16 - b
m = (16 - b) / 4
We know that m passes through (4,16), so plugging in these values gives us:
16 = m(4) + b
16 = (16 - b) + b
16 = 16
Thus, the slope-intercept equation of the line is y = x + 0 or simply y = x.